いろいろ 2x/y^3dx y^2-3x^2/y^4dy=0 392951-2x/y^3dx+y^2-3x^2/y^4dy=0 nyosspixinii

Given, (6x4y1)dy= (3x2y1) dx ️ dy/dx=(3x2y1)/(6x4y1)(i) In which, a=3 b= (2) & a1= 6 & b1= (4) {Since, We know that, If dy/dx= (axby...

[コンプリート！] �a�n�z�x 310783-A n s xtreme performance nyosspixinii

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